Can The Circuit Shown Be Reduced To A Single Resistor
I have a question ...? 3
(a) The circuit in Fig. P18.25 is connected to a single resistor
Drums? please explain.
(b) Calculate the corresponding unknown current I1, I2 and I3 for the circuit.
a) No, the circuit cannot be reduced to one resistor.
B. Simplify both networks.
Above 2 + 4 = 6 ohms
Lower 1 + 5 = 6 ohms
Rebuild the simple circuit. Note: i3 = i1i2. Ohm's law =>
6 * i1 (i1i2) * 3 + 24 = 0 ......... (1)
3 * (i1i2) 6 * i2 + 12 = 0 ........... (2)
9i1 + 3i2 + 24 = 0 .................... (1)
3i1 9i2 + 12 = 0 ................................. (2), divide by 3 and => Add
8i1 + 28 = 0 => i1 = 3.5 A => i2 = 2.5 A and i3 = i1i2 = 1 A
(i1, i2, i3) = (3.5A, 2.5A, 1A)
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Circuits can be shortened but one cannot be made.
You can equate three elements and you have three unknown ones.
